Timeline for Lattice points inside $x^2+y^2=r^2$
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
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| Jun 24 at 5:37 | comment | added | Kamal Saleh | Couldn't this be done by Pick's Theorem? | |
| Jun 24 at 5:33 | history | edited | Bob Dobbs | CC BY-SA 4.0 |
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| Jun 24 at 0:14 | comment | added | colt_browning | Well, the interior of the square of side length $N=5$ with vertices at $(0,0)$, $(4,3)$ [and two more] has $24$ interior points rather than $(N-1)^2=16$. | |
| Jun 23 at 16:17 | comment | added | Keplerto | It reminds me of this famous video. It doesn't really adress your question though. youtube.com/watch?v=NaL_Cb42WyY | |
| Jun 23 at 16:14 | comment | added | Joshua Wang | Here is the relevant Wiki page: en.wikipedia.org/wiki/Gauss_circle_problem. The best known-bound on the difference between the number of lattice points and $\pi r^{2}$ is $O(r^{0.63})$. | |
| Jun 23 at 16:01 | history | edited | Bob Dobbs | CC BY-SA 4.0 |
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| Jun 23 at 15:58 | history | undeleted | Bob Dobbs | ||
| Jun 23 at 15:53 | history | deleted | Bob Dobbs | via Vote | |
| Jun 23 at 15:45 | history | asked | Bob Dobbs | CC BY-SA 4.0 |