Timeline for Does the monoid of non-zero representations with the tensor product admit unique factorization?

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when toggle format	what		by	license	comment
Jun 22 at 20:38	comment	added	Qiaochu Yuan		It's notation that gets used in some corners of geometric representation theory. There people do things like take $G$ to be an algebraic group and consider the quotient $G/G$ in a stacky sense.
Jun 22 at 20:37	comment	added	Smiley1000		Thanks. Although I must admit that writing $G/G$ and implying the action by conjugation is something I've never seen before, perhaps also a little too ambiguous.
Jun 22 at 20:35	comment	added	Qiaochu Yuan		@Smiley1000: here $G/G$ means the quotient of $G$ by the action of $G$ by conjugation, so it denotes the set of conjugacy classes. Then a function $G/G \to \mathbb{C}$ is a complex-valued function on the set of conjugacy classes. By "representation ring over $\mathbb{C}$" I meant $R(G) \otimes \mathbb{C}$, I guess that was ambiguous.
Jun 22 at 20:33	comment	added	Smiley1000		What do you mean by "$G/G \to \mathbb{C}$"? Also, doesn't this confuse the representation ring $R(G)$ with the algebra $R(G) \otimes \mathbb{C}$?
Jun 22 at 20:32	vote	accept	Smiley1000
Jun 22 at 19:18	history	answered	Qiaochu Yuan	CC BY-SA 4.0