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Jun 19 at 20:40 comment added Turquoise Tilt Ok I get what you're trying to do in rotating the coordinate to fit the circumference. My thought is, wouldn't work the same if i'm rotating the axe where $Q$ live? For the circumference I would use usual polar coordinates and I will apply a reasoning similar to yours for the rotated axe. Why I will go the other way round? To me seems easier honestly...
Jun 19 at 20:13 history answered Egor Larionov CC BY-SA 4.0