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Jun 24 at 6:39 history edited thefool CC BY-SA 4.0
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Jun 23 at 21:08 vote accept thefool
Jun 17 at 4:52 comment added user2661923 See also this answer for an explanation of and justification for the Inclusion-Exclusion formula.
Jun 17 at 4:47 comment added user2661923 +1 to your accurate and valid answer. My only constructive criticism is to suggest that in general with such problems, you (alternatively) express the probability as something like $~\dfrac{A}{D} ~: ~D = (52)^N.~$ So, you compute $~A~$ combinatorically, using Inclusion-Exclusion, bypassing any considerations of probability, thus (arguably) making things easier on yourself. You might end up with something like $$A = \sum_{k=0}^{52} (-1)^{k} \binom{52}{k} (52-k)^N.$$
Jun 16 at 18:44 history answered thefool CC BY-SA 4.0