Timeline for What is the probability of getting 2 chosen ranked cards (any suit). Before the dealer, when the cards are dealt alternately starting from the player?
Current License: CC BY-SA 4.0
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Jun 6 at 6:49 | comment | added | ploosu2 | @DanielMathias Yes, the probability of a tie is $0.00848566376905302$. | |
Jun 6 at 6:22 | answer | added | ploosu2 | timeline score: 0 | |
Jun 6 at 2:47 | history | edited | RobPratt |
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Jun 5 at 23:33 | comment | added | Daniel Mathias | The win condition is not clearly stated. Is it drawing one of each chosen rank? If so, there is the possibility that there is no winner. | |
Jun 5 at 8:57 | history | edited | Shaun Andrew | CC BY-SA 4.0 |
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Jun 5 at 7:06 | comment | added | Shaun Andrew | A single chosen rank and suit, is easier then the stated problem. As in the problem, the dealer can match the 2 ranked cards before the player resulting in a loss, even if the player has 2 matches themselves. | |
Jun 5 at 6:55 | comment | added | EnEm | This problem is not nearly as difficult as the plane boarding one. Try for example to find the probability of a chosen card( with a certain rank and suit) being dealt to the player. If you can understand this is just $1/2$ because of odd and even positions, then you can proceed onto this with ease | |
Jun 5 at 6:45 | history | edited | Shaun Andrew | CC BY-SA 4.0 |
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Jun 5 at 6:42 | history | edited | Shaun Andrew | CC BY-SA 4.0 |
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Jun 5 at 6:38 | history | edited | Shaun Andrew | CC BY-SA 4.0 |
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Jun 5 at 6:36 | history | edited | Shaun Andrew | CC BY-SA 4.0 |
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Jun 5 at 6:28 | comment | added | CommunityBot | Please clarify your specific problem or provide additional details to highlight exactly what you need. As it's currently written, it's hard to tell exactly what you're asking. | |
Jun 5 at 6:26 | comment | added | J.D | Welcome to MSE: What have you tried? | |
Jun 5 at 6:22 | history | edited | Shaun Andrew | CC BY-SA 4.0 |
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S Jun 5 at 6:21 | review | First questions | |||
Jun 5 at 6:28 | |||||
S Jun 5 at 6:21 | history | asked | Shaun Andrew | CC BY-SA 4.0 |