Timeline for Why is the distributive law incorrect here?
Current License: CC BY-SA 4.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Mar 8 at 8:05 | vote | accept | Alix Blaine | ||
| Mar 8 at 8:00 | answer | added | Alix Blaine | timeline score: 0 | |
| Mar 6 at 16:14 | history | edited | Bram28 |
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| Mar 6 at 14:20 | answer | added | Bram28 | timeline score: 1 | |
| Mar 5 at 20:34 | comment | added | fleablood | Two wrongs making a right. $q\lor\lnot q = T$ and $p\lor T = T$ (not $p$) so your third step is wrong. But as @TonyK points out you should have $q\land \lnot q$ and not $q\lor \lnot q$. $q\land\lnot q= F$ and so you should actually have $p\lor F$ rather thn $p\lor T$. And $p\lor F = p$. | |
| Mar 5 at 17:27 | comment | added | TonyK | Your Step 2 should be $p \lor (q \land \neg q)$, not $p \lor (q \lor \neg q)$. | |
| Mar 5 at 17:22 | history | asked | Alix Blaine | CC BY-SA 4.0 |