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Nov 13, 2023 at 16:51 comment added Henry If you do not take into account the earlier cards (e.g. by not looking at them), the probability of a tie in any particular later pair will remain the same as it was for the first pair, by exchangeability, and so the house edge will remain the same. Your observation "the expected value was exactly the same" is therefore not a surprise. Your weighted probability calculation for the second pair illustrates this.
Nov 13, 2023 at 16:51 answer added mihaild timeline score: 1
S Nov 13, 2023 at 16:39 review First questions
Nov 13, 2023 at 16:50
S Nov 13, 2023 at 16:39 history asked wzq31757 CC BY-SA 4.0