Timeline for Compute $\sum^{2024}_{k=1} \frac{2023-2022 \cos \left(\frac{\pi(2k-1)}{2024} \right)}{2021-2020 \cos \left(\frac{\pi(2k-1)}{2024} \right)}$
Current License: CC BY-SA 4.0
13 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 23, 2023 at 18:31 | audit | Reopen votes | |||
| Oct 23, 2023 at 18:33 | |||||
| Oct 18, 2023 at 10:24 | audit | Close votes | |||
| Oct 18, 2023 at 12:49 | |||||
| Oct 8, 2023 at 15:03 | vote | accept | Indecisive | ||
| Oct 7, 2023 at 21:11 | audit | Close votes | |||
| Oct 7, 2023 at 21:11 | |||||
| Oct 7, 2023 at 4:02 | answer | added | metamorphy | timeline score: 4 | |
| Sep 28, 2023 at 23:46 | comment | added | Indecisive | @EricSnyder Putting it into a calculator, the sum I am trying to find is about 64315, but the sum in my complex numbers approach is about 1479. I believe the issue arises from the imaginary part of the complex number contributing to the value of the denominator (if you were to multiply the numerator and denominator by the complex conjugate). | |
| Sep 28, 2023 at 21:56 | comment | added | Eric Snyder | I'm looking again at your route using the complex numbers and wondering why that doesn't work. It sure looks like it ought to. | |
| Sep 28, 2023 at 2:09 | comment | added | Indecisive | @user376343 Ran across it as a question someone asked on a Discord server, don't know much more than that | |
| Sep 26, 2023 at 8:07 | comment | added | user376343 | @Indecisive can you reveal the source? | |
| Sep 26, 2023 at 0:36 | history | edited | Indecisive | CC BY-SA 4.0 |
added 54 characters in body
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| Sep 25, 2023 at 22:32 | comment | added | Eric Snyder | Also FWIW, Sagemath returns $2025.9724361499493...$, which is not quite the same as W|A's answer out in the 12th decimal place. Not sure if this helps at all. (Note: Sagemath loves integers and isn't so fond of reals; W|A may be more precise here.) | |
| Sep 25, 2023 at 22:17 | comment | added | Dan | FWIW, Wolfram Alpha gives the numerical answer of $2025.972436149946$, but fails to find an exact form that's simpler than the summation. | |
| Sep 25, 2023 at 17:13 | history | asked | Indecisive | CC BY-SA 4.0 |