Timeline for How deduce $\prod_{k=1}^{(n-1)/2} \sin^2 \frac{k\pi}{n} =\frac{n}{2^{n-1}}$ from $\prod_{k=1}^{n-1} \sin \frac{k\pi}{n} =\frac{n}{2^{n-1}}$?
Current License: CC BY-SA 4.0
11 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Aug 28, 2023 at 22:23 | comment | added | Kamal Saleh | Please write what you have tried to solve the problem. You have four close votes for this issue. I personally won't vote though because nobody told you this. @ThomasAndrews You could make your hint an answer because it makes the problem straightforward. | |
| Aug 28, 2023 at 13:29 | comment | added | Thomas Andrews | Yes, the same hint applies, you just no longer need $\sin\frac\pi2=1$ when $n$ is odd. | |
| Aug 28, 2023 at 5:37 | comment | added | user | The hint of @ThomasAndrews works in this case as well. | |
| Aug 27, 2023 at 23:50 | review | Close votes | |||
| Aug 28, 2023 at 22:24 | |||||
| Aug 27, 2023 at 21:33 | comment | added | Liam | Corrected. I replace even by odd. Sorry. | |
| Aug 27, 2023 at 21:32 | history | edited | Liam | CC BY-SA 4.0 |
deleted 1 character in body
|
| Aug 27, 2023 at 21:03 | comment | added | user | It should be probably $n/2-1$ instead of $(n-1)/2$ in the second equation. | |
| S Aug 27, 2023 at 17:45 | history | suggested | Math Admiral | CC BY-SA 4.0 |
deleting repeated word
|
| Aug 27, 2023 at 17:32 | comment | added | Thomas Andrews | Hint:$\sin(x)=\sin(\pi-x)$ and $\sin(\pi/2)=1.$ | |
| Aug 27, 2023 at 17:28 | review | Suggested edits | |||
| S Aug 27, 2023 at 17:45 | |||||
| Aug 27, 2023 at 17:27 | history | asked | Liam | CC BY-SA 4.0 |