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Jul 27, 2023 at 7:03 comment added Therkel You can replace $1/2^n$ with $p^{n-2k} (1-p)^{2k}$ if you want a generalized version of the above with a skewed coin with probability $p\in(0,1)$ for heads.
Jul 24, 2023 at 22:31 history edited Ennar CC BY-SA 4.0
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Jul 24, 2023 at 12:28 history answered Ennar CC BY-SA 4.0