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May 30, 2023 at 9:50 comment added Sassatelli Giulio About your side question on the cardinality of $B$ (of course with AC), for a cardinal $\kappa$ the following are equivalent: 1) there is a subfield $F\subseteq \Bbb R$ such that $\dim_F(\Bbb R)=\kappa$; 2) $\kappa=1\lor \aleph_0\le \kappa\le \lvert \Bbb R\rvert$.
May 30, 2023 at 9:28 comment added Dave L. Renfro For some decompositions that go a bit beyond purely set-theoretic constructions (in size and/or in "naturalness"), see my answer to Using transfinite induction to split $R$ to continuum many pairwise disjoint subsets of $R$ AND A partition of the unit interval into uncountably many dense uncountable subsets AND my answer to Are there sets of zero measure and full Hausdorff dimension?.
May 30, 2023 at 8:33 comment added Anne Bauval Hint: $\mathbb{R}^2$ has the cardinality of the continuum.
May 30, 2023 at 8:26 comment added Anne Bauval Your $B$ may be a singleton.
May 30, 2023 at 8:15 history asked Ifielmodes CC BY-SA 4.0