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Apr 12, 2023 at 19:09 history edited GReyes CC BY-SA 4.0
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Apr 12, 2023 at 19:01 comment added GReyes @krm2233 You are absolutely right of course. I will correct my answer.
Apr 12, 2023 at 18:10 comment added krm2233 Indeed having managed to track down PMA, Rudin's point in giving this construction is to show that monotonic functions can be discontinuous at a dense set of points in their domain of definition: the function $f$ is continuous everywhere except on $E=\{x_n: n \in \mathbb N\}$. (Monotonic functions on an interval can have at most countably many discontinuities however.)
Apr 12, 2023 at 17:11 comment added krm2233 The claim that $f$ is constant "close enough to $x_n$ for $x>x_n$ or $x<x_n$ is not correct. The set $\{x_n\}$ could be dense in $(a,b)$.
Apr 12, 2023 at 16:37 history answered GReyes CC BY-SA 4.0