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Dunham
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Consider this example: $(a,b) = (0,1)$ with $x_1= 3/4$, $x_2=1/2$, $c_1 = 1$, and $c_2=2$. Then \begin{equation*} f(x) = \begin{cases} 0, & x \leq \frac{1}{2}\\ 2, & \frac{1}{2} < x \leq \frac{3}{4}\\ 3, & \frac{3}{4} <x \end{cases} \end{equation*}

It seems to me that the order is irrelevant as noted by Rudin.

Note The comment below of krm2233 gives a nice explanation of how this example is constructed from the definition

Consider this example: $(a,b) = (0,1)$ with $x_1= 3/4$, $x_2=1/2$, $c_1 = 1$, and $c_2=2$. Then \begin{equation*} f(x) = \begin{cases} 0, & x \leq \frac{1}{2}\\ 2, & \frac{1}{2} < x \leq \frac{3}{4}\\ 3, & \frac{3}{4} <x \end{cases} \end{equation*}

It seems to me that the order is irrelevant as noted by Rudin.

Consider this example: $(a,b) = (0,1)$ with $x_1= 3/4$, $x_2=1/2$, $c_1 = 1$, and $c_2=2$. Then \begin{equation*} f(x) = \begin{cases} 0, & x \leq \frac{1}{2}\\ 2, & \frac{1}{2} < x \leq \frac{3}{4}\\ 3, & \frac{3}{4} <x \end{cases} \end{equation*}

It seems to me that the order is irrelevant as noted by Rudin.

Note The comment below of krm2233 gives a nice explanation of how this example is constructed from the definition

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Dunham
  • 3.3k
  • 12
  • 19

Consider this example: $(a,b) = (0,1)$ with $x_1= 3/4$, $x_2=1/2$, $c_1 = 1$, and $c_2=2$. Then \begin{equation*} f(x) = \begin{cases} 0, & x \leq \frac{1}{2}\\ 2, & \frac{1}{2} < x \leq \frac{3}{4}\\ 3, & \frac{3}{4} <x \end{cases} \end{equation*}

It seems to me that the order is irrelevant as noted by Rudin.