Timeline for Does an invertible real matrix have a real cubic root
Current License: CC BY-SA 4.0
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| when toggle format | what | by | license | comment | |
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| Nov 22, 2022 at 7:26 | comment | added | noname1014 | is there an $A$ which is an invertible real matrix, but there is no real matrix $B$ such that $A=B^3$? | |
| Nov 22, 2022 at 5:26 | comment | added | mr_e_man | What if it's not diagonalizable? For example $$A=\begin{bmatrix}1&1\\0&1\end{bmatrix}$$ does have a cube root $$\begin{bmatrix}1&1/3\\0&1\end{bmatrix}$$ but your method doesn't apply to it. | |
| Nov 22, 2022 at 4:39 | history | answered | P. Lawrence | CC BY-SA 4.0 |