Timeline for Probability that there exist at least one day without any Birthday
Current License: CC BY-SA 4.0
7 events
| when toggle format | what | by | license | comment | |
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| Aug 13, 2022 at 13:06 | comment | added | Salcio | This is so counter-intuitive ... one would guess that with 365 people probability should be much bigger. Brings to mind another problem - how many people you need in a room so that with probability of at least 0.5 two of them were born on the same day of the year. The answer is around 23. | |
| Aug 13, 2022 at 12:28 | vote | accept | Baban Gain | ||
| Aug 12, 2022 at 17:17 | history | edited | Henry |
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| Aug 12, 2022 at 17:17 | answer | added | Henry | timeline score: 2 | |
| Aug 4, 2022 at 21:09 | comment | added | Sassatelli Giulio | You want $1-365^{-N} X_N$, where $X_N$ is the number of surjective maps $\{1,\cdots, N\}\to \{1,\cdots, 365\}$. This is $X_N=365!\left\{\begin{matrix} N\\ 365\end{matrix}\right\}$, where $\left\{\begin{matrix} n\\ k\end{matrix}\right\}$ is the Stirling number of the second kind. | |
| S Aug 4, 2022 at 20:58 | review | First questions | |||
| Aug 4, 2022 at 21:04 | |||||
| S Aug 4, 2022 at 20:58 | history | asked | Baban Gain | CC BY-SA 4.0 |