Timeline for asymptotic order in probability
Current License: CC BY-SA 4.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Dec 24, 2021 at 15:55 | comment | added | user140541 | @CelineHarumi That's correct. You can also notice that $F_{X_n}(x)$ converges to $1_{[1,\infty)}(x)$, which leads to the same conclusion: any $M<1$ works. | |
| Dec 24, 2021 at 15:47 | comment | added | Celine Harumi | Ok, as $\epsilon$ is arbitrary, any $M<1$ works. | |
| Dec 24, 2021 at 15:35 | comment | added | Celine Harumi | Wait, can you explain me the last line? why the first expression implies the second? | |
| Dec 24, 2021 at 14:45 | vote | accept | Celine Harumi | ||
| Dec 24, 2021 at 14:34 | history | answered | user140541 | CC BY-SA 4.0 |