Here $x_1>0$ is the initial condition and $x_{n+1}$ is defined by

$$x_{n+1}=\Big[\frac{1}{n}\sum_{k=1}^n x_k^2 -\frac{1}{n^2}\Big(\sum_{k=1}^n x_k\Big)^2 \Big]^{1/2}. $$ Clearly, $x_n=\lambda_n \cdot x_1$ where $\lambda_1,\lambda_2,\dots$ is a sequence of positive real numbers not depending on the initial condition $x_1$. For instance, $\lambda_1=1,\lambda_2=0$. It seems, based on empirical evidence, that $\lambda_n\sim \gamma \cdot n^\alpha$ for some constants $\gamma\approx 0.54$ and $\alpha\approx-0.35$.

Substituting $x_k$ by its asymptotic expansion in the first formula defining the sequence $(x_n)$, one gets the following, after trivial computations and rearrangements: $\alpha^2=(2\alpha+1)(\alpha+1)^2$. Let $\tau=(13+3\sqrt{33})^{1/3}$. Then we have, according to Mathematica:

$$\alpha=\frac{1}{3}\Big(-2-\frac{2^{5/3}}{\tau}+\frac{\tau}{2^{2/3}}\Big)\approx-0.3522011.$$

Is this correct? Also, I could not find how to determine the value of $\gamma$. Could you express $\gamma$ as a solution of some equation (as I did for $\alpha$) or using a series or anything else?

Here $x_1>0$ is the initial condition and $x_{n+1}$ is defined by

$$x_{n+1}=\Big[\frac{1}{n}\sum_{k=1}^n x_k^2 -\frac{1}{n^2}\Big(\sum_{k=1}^n x_k\Big)^2 \Big]^{1/2}. $$ Clearly, $x_n=\lambda_n \cdot x_1$ where $\lambda_1,\lambda_2,\dots$ is a sequence of positive real numbers not depending on the initial condition $x_1$. For instance, $\lambda_1=1,\lambda_2=0$. It seems, based on empirical evidence, that $\lambda_n\sim \gamma \cdot n^{-\alpha}$ for some constants $\gamma\approx 0.54$ and $\alpha\approx 0.35$.

Substituting $x_k$ by its asymptotic expansion in the first formula defining the sequence $(x_n)$, one gets the following, after trivial computations and rearrangements: $\alpha^2=(1-2\alpha)(1-\alpha)^2$. Let $\tau=(13+3\sqrt{33})^{1/3}$. Then we have, according to Mathematica:

$$\alpha=\frac{1}{3}\Big(2+\frac{2^{5/3}}{\tau}-\frac{\tau}{2^{2/3}}\Big)\approx 0.3522011.$$

Is this correct? Also, I could not find how to determine the value of $\gamma$. Could you express $\gamma$ as a solution of some equation (as I did for $\alpha$) or using a series or anything else?

Here $x_1>0$ is the initial condition and $x_{n+1}$ is defined by

$$x_{n+1}=\Big[\frac{1}{n}\sum_{k=1}^n x_k^2 -\frac{1}{n^2}\Big(\sum_{k=1}^n x_k\Big)^2 \Big]^{1/2}. $$ Clearly, $x_n=\lambda_n \cdot x_1$ where $\lambda_1,\lambda_2,\dots$ is a sequence of positive real numbers not depending on the initial condition $x_1$. For instance, $\lambda_1=1,\lambda_2=0$. It seems, based on empirical evidence, that $\lambda_n\sim \gamma \cdot n^\alpha$ for some constants $\gamma\approx 0.54$ and $\alpha\approx-0.35$.

Substituting $x_k$ by its asymptotic expansion in the first formula defining the sequence $(x_n)$, one gets the following, after trivial computations and rearrangements: $\alpha^2=(2\alpha+1)(\alpha+1)^2$. Let $\tau=(13+3\sqrt{33})^{1/3}$. Then we have, according to Informatica:

$$\alpha=\frac{1}{3}\Big(-2-\frac{2^{5/3}}{\tau}+\frac{\tau}{2^{2/3}}\Big)\approx-0.3522011.$$

Is this correct? Also, I could not find how to determine the value of $\gamma$. Could you express $\gamma$ as a solution of some equation (as I did for $\alpha$) or using a series or anything else?

Here $x_1>0$ is the initial condition and $x_{n+1}$ is defined by

$$x_{n+1}=\Big[\frac{1}{n}\sum_{k=1}^n x_k^2 -\frac{1}{n^2}\Big(\sum_{k=1}^n x_k\Big)^2 \Big]^{1/2}. $$ Clearly, $x_n=\lambda_n \cdot x_1$ where $\lambda_1,\lambda_2,\dots$ is a sequence of positive real numbers not depending on the initial condition $x_1$. For instance, $\lambda_1=1,\lambda_2=0$. It seems, based on empirical evidence, that $\lambda_n\sim \gamma \cdot n^\alpha$ for some constants $\gamma\approx 0.54$ and $\alpha\approx-0.35$.

Substituting $x_k$ by its asymptotic expansion in the first formula defining the sequence $(x_n)$, one gets the following, after trivial computations and rearrangements: $\alpha^2=(2\alpha+1)(\alpha+1)^2$. Let $\tau=(13+3\sqrt{33})^{1/3}$. Then we have, according to Mathematica:

$$\alpha=\frac{1}{3}\Big(-2-\frac{2^{5/3}}{\tau}+\frac{\tau}{2^{2/3}}\Big)\approx-0.3522011.$$

Is this correct? Also, I could not find how to determine the value of $\gamma$. Could you express $\gamma$ as a solution of some equation (as I did for $\alpha$) or using a series or anything else?