Skip to main content
15 events
when toggle format what by license comment
Jun 9, 2023 at 1:07 comment added orangeskid Your idea definitely works. Say consider distinct prime numbers $p_k$, and $a_k = \sqrt{p_k}$. Then every matrix composed of the $a_k$ is invertible. The point is that real radicals that are incommensurable are also linearly independent over $\mathbb{Q}$, proved elsewhere.
Jun 17, 2021 at 5:52 audit Close votes
Jun 17, 2021 at 5:53
Jun 15, 2021 at 23:18 audit Reopen votes
Jun 15, 2021 at 23:18
Jun 10, 2021 at 2:35 audit Close votes
Jun 10, 2021 at 2:35
May 23, 2021 at 7:30 history removed from network questions Asaf Karagila
May 23, 2021 at 5:06 history became hot network question
S May 23, 2021 at 5:06 history became hot network question
S May 23, 2021 at 5:06 history became hot network question
S May 23, 2021 at 5:06 history became hot network question
S May 23, 2021 at 5:06 history became hot network question
S May 23, 2021 at 5:06 history became hot network question
May 22, 2021 at 21:24 vote accept Jujustum
May 22, 2021 at 21:14 answer added orangeskid timeline score: 7
May 22, 2021 at 21:07 review First posts
May 22, 2021 at 21:08
May 22, 2021 at 21:06 history asked Jujustum CC BY-SA 4.0