Timeline for The winning probability in a card game
Current License: CC BY-SA 4.0
14 events
| when toggle format | what | by | license | comment | |
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| Jul 3, 2020 at 16:41 | comment | added | Masacroso | @weilam06 it will be easier to compute manually these probabilities if we assume draw with replacement. It will be interesting to see how much different have the probabilities assuming replacement and assuming without replacement, I guess that the difference will be small maybe around 1-2% or so of difference | |
| Jul 3, 2020 at 15:33 | vote | accept | weilam06 | ||
| Jul 3, 2020 at 15:33 | comment | added | weilam06 |
Thanks. This simplifies a lot with python.
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| Jul 3, 2020 at 7:55 | comment | added | weilam06 | @Masacroso Is that any efficient way to calculate $P[\max H_1>\max H_2]$ etc? | |
| Jul 2, 2020 at 17:52 | history | edited | Masacroso | CC BY-SA 4.0 |
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| Jul 2, 2020 at 17:25 | comment | added | Masacroso | @weilam06 I added the general case | |
| Jul 2, 2020 at 17:25 | history | edited | Masacroso | CC BY-SA 4.0 |
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| Jul 2, 2020 at 17:19 | comment | added | saulspatz | But it is given that both players have a "tendency". | |
| Jul 2, 2020 at 17:17 | history | edited | Masacroso | CC BY-SA 4.0 |
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| Jul 2, 2020 at 17:09 | comment | added | Masacroso | @weilam06 Im assuming that player one play a card randomly, that is, that it doesnt have a strategy, so we can assume that it draw just one card (or that the fourth drawn card is for the player one) | |
| Jul 2, 2020 at 17:00 | comment | added | weilam06 | I think your idea will work. But I don’t understand the case that reduce to 3 cards drawing. Which card do you remove from $P_1$ or $P_2$? And Pr$[P_1$ wins $\lvert P_2$ took its higher card$]$= Pr$[P_1$ wins with lower card $\lvert P_2$ took its higher card$]$+ Pr$[P_1$ wins with higher card$\lvert P_2$ took its higher card$]$? | |
| Jul 2, 2020 at 16:54 | history | edited | Masacroso | CC BY-SA 4.0 |
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| Jul 2, 2020 at 16:47 | history | edited | Masacroso | CC BY-SA 4.0 |
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| Jul 2, 2020 at 16:42 | history | answered | Masacroso | CC BY-SA 4.0 |