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Mar 25, 2019 at 19:04 vote accept jmarvin_
Mar 25, 2019 at 19:04
Mar 24, 2019 at 15:27 comment added coffeemath @TomislavOstojich No contradiction.. $f$ differentiable always, but $f'$ (not $f$) isn't always.
Mar 24, 2019 at 15:27 comment added MachineLearner @TomislavOstojich I think you didn't notice the prime. I said that $f(x)$ differentiable. And $f'(x)$ (the derivative of f(x)$ is not differentiable.
Mar 24, 2019 at 15:05 history answered MachineLearner CC BY-SA 4.0