Timeline for Does connected components of a group scheme form a group scheme?
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
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| Apr 7, 2022 at 21:49 | answer | added | Takagi Benseki | timeline score: 2 | |
| Apr 3, 2019 at 10:09 | vote | accept | CommunityBot | ||
| Apr 3, 2019 at 9:23 | answer | added | Alex Youcis | timeline score: 0 | |
| Jan 10, 2019 at 18:02 | history | edited | user395911 | CC BY-SA 4.0 |
added 20 characters in body
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| Jan 10, 2019 at 16:31 | comment | added | Mohan | I don't think it does. You have a group homomorphism $G\to \pi_0(G)$ and the fiber over $e$ is a normal subgroup. The fiber over other points of $\pi_0(G)$ are not subgroups. | |
| Jan 10, 2019 at 14:56 | comment | added | user395911 | @Mohan Milne has a section "The group of connected components of an algebraic group" at jmilne.org/math/CourseNotes/iAG200.pdf, and I think that works well over a field. | |
| Jan 10, 2019 at 14:35 | comment | added | Mohan | If $S$ is spectrum of a field and $G$ is a finite group, the connected components are not group schemes (at least not in a natural way, except the identity component). | |
| Jan 10, 2019 at 6:45 | history | asked | user395911 | CC BY-SA 4.0 |