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S Jul 15, 2018 at 8:55 history suggested Noa Even CC BY-SA 4.0
improved formatting
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S Jul 15, 2018 at 8:55
Jul 13, 2018 at 20:23 vote accept Student
Jul 13, 2018 at 20:14 answer added mechanodroid timeline score: 1
Jul 13, 2018 at 20:05 history edited Student CC BY-SA 4.0
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Jul 13, 2018 at 20:05 comment added user574380 What I said is such a proof, because you will use your argument above, which is one.
Jul 13, 2018 at 20:03 comment added Student Thanks, but I am looking for a 'classic proof', using $n_0-\epsilon$. This question is one after basic results on convergent sequences (sum, difference, quotient rules etc.)
Jul 13, 2018 at 20:00 comment added user574380 You can always take bijections $a:\mathbb{N}\to y^{-1}((0,\infty))$ and $b:\mathbb{N}\to y^{-1}((-\infty,0))$ and apply your argument above (which is correct) to $x_{a_n}/y_{a_n}$ and to $x_{b_n}/y_{b_n}$. On the other hand, the proof cannot be the analysis of the single example that you have at the end. You want to prove the general statement, that for every $y_n\to0$ without definite sign and $x_n\to x$, the limit of $x_n/y_n$ is not one of $\pm\infty$.
Jul 13, 2018 at 19:47 history asked Student CC BY-SA 4.0