Skip to main content
17 events
when toggle format what by license comment
Jul 6, 2018 at 10:40 answer added user562983 timeline score: 3
Jul 6, 2018 at 9:48 vote accept Alex Silva
Jul 6, 2018 at 9:30 answer added user856 timeline score: 4
Jul 6, 2018 at 9:27 comment added Alex Silva @user550103, I added it up.
Jul 6, 2018 at 9:26 history edited Alex Silva CC BY-SA 4.0
antoher example
Jul 6, 2018 at 9:22 comment added user550103 @AlexSilva: Ok, I see. Probably, this example should be added as an example in the above problem.
Jul 6, 2018 at 9:22 comment added user562983 The reason why it can't be true in a meaningful way is the reason why convex optimization is nice: local minima of a convex function are global minima, i.e. if there is some $x$ and some neigbourhood $U$ of $x$ such that $f(y)\ge f(x)$ for all $y\in U$, then $f(y)\ge f(x)$ for all $y$. If $f$ takes distinct values in many distinct local minima, then $f\circ g$ must "forget" that topological obstruction. A convex function covers intervals as a homeomorphism, as a $\cup$-thing or as a $\setminus\underline\quad/$-thing. So $f\circ g$ can't forget about those local minima (unless $g$ avoids them).
Jul 6, 2018 at 9:11 comment added Alex Silva @user550103, $f(x) = x^3$ and $g(x) = \begin{cases} -x, ~\text{if}~ x < 0\\ x, ~\text{if}~ x \geq 0 \end{cases}$.
Jul 6, 2018 at 9:00 answer added Martin R timeline score: 6
Jul 6, 2018 at 8:52 comment added user550103 @AlexSilva Do you have a better example instead of such a simple concave function? some other non-convex function that is mapped to a convex function?
Jul 6, 2018 at 8:48 history edited Alex Silva CC BY-SA 4.0
clarification
Jul 6, 2018 at 8:44 comment added Alex Silva @user550103, I agree, but it is just an example. It does not work if $f$ is not concave.
Jul 6, 2018 at 8:42 comment added Alex Silva @MartinR Thanks for your reply, but I am not interested in the trivial solution $g$ constant.
Jul 6, 2018 at 8:38 comment added Martin R Any constant function $g$ would do that, but you are probably looking for strictly monotonic (injective) functions.
Jul 6, 2018 at 8:37 comment added user550103 just a side comment with a clarification. $\log(x)$ is a concave function. So, negated concave should yield convex, agree?
Jul 6, 2018 at 8:37 comment added user562983 I presume $g$ surjective?
Jul 6, 2018 at 8:31 history asked Alex Silva CC BY-SA 4.0