Timeline for Has $\sigma\left(\sigma_0(n)^4\right)=n$ infinitely many solutions?
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| Jun 6, 2018 at 9:03 | comment | added | user243301 | Many thanks @didgogns again for your new calculations, your work was a professional work $100$% and thanks to the user editing the post. On the other hand you can see it from the web of Crux Mathematicorum, choose the Volume 37 (that is the year 2011)> Oct > Solutions... Feel free to study equations that can be stated as generalization, I am an amateur and I cann't do it. | |
| Jun 6, 2018 at 7:22 | history | edited | Antonio Vargas |
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| Jun 6, 2018 at 5:52 | comment | added | didgogns | By the way, what was the original Problem 3565, Crux Mathematicorum, Volume 37, Number 6? | |
| Jun 4, 2018 at 16:25 | vote | accept | CommunityBot | ||
| Jun 4, 2018 at 16:11 | answer | added | didgogns | timeline score: 3 | |
| Jun 4, 2018 at 13:52 | comment | added | user243301 | I think that also there are only a finite number of solutions ( and I know that my words contradict my conjecture, but my computations don't offer me more), I tried to combine the size of the divisor-counting function and inequalities from the literature about the maximal size of the sum of divisors function @didgogns , but my attempt was failed. | |
| Jun 4, 2018 at 13:49 | comment | added | didgogns | Since $\sigma$ is multiplicative function, the product of two relatively prime solutions is also solution. For example, $31 \times 121=3751$. However, I feel like there are only finite number of solutions... | |
| Jun 4, 2018 at 12:59 | review | Close votes | |||
| Jun 4, 2018 at 15:53 | |||||
| Jun 4, 2018 at 12:32 | history | asked | user243301 | CC BY-SA 4.0 |