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Feb 19, 2018 at 20:04 comment added seba It's trivial that it does not work—just try $n=c=2$, $m=4$.
Feb 19, 2018 at 16:14 comment added Arthur The cases where more than one bin is overflowed is overcounted in this method (at least if you were thinking of taking the probability of $x_1\geq c$ and multiply by $n$).
Feb 19, 2018 at 16:05 comment added Mostafa Ayaz since $x_1-c=y_1\ge 0$ so it contains both cases
Feb 19, 2018 at 16:04 comment added Mostafa Ayaz Of course it does since there is no constraint on the rest of the $x_i$'s
Feb 19, 2018 at 16:03 history edited Mostafa Ayaz CC BY-SA 3.0
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Feb 19, 2018 at 16:03 comment added Ross Millikan This does not reflect the times one bin gets more than $c$ nor the times more than one bin gets $c$.
Feb 19, 2018 at 16:01 history answered Mostafa Ayaz CC BY-SA 3.0