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Jan 2, 2018 at 11:41 vote accept roymend
Jan 2, 2018 at 1:06 history edited hmakholm left over Monica CC BY-SA 3.0
added 24 characters in body
Jan 2, 2018 at 1:05 comment added Asaf Karagila Even with different $\Bbb N$'s, they can have completely different second-order models, since those depend on $\mathcal P(\Bbb N)$.
Jan 2, 2018 at 1:02 history answered hmakholm left over Monica CC BY-SA 3.0