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You want to determine if $(\frac{101}{100})^{100}\geq 100$$\left(\frac{101}{100}\right)^{100}\geq 100$. But we know that $ \left(1+\frac{1}{n}\right)^n$ is always less than $e$.
You want to determine if $(\frac{101}{100})^{100}\geq 100$. But we know that $ \left(1+\frac{1}{n}\right)^n$ is always less than $e$.
You want to determine if $\left(\frac{101}{100}\right)^{100}\geq 100$. But we know that $ \left(1+\frac{1}{n}\right)^n$ is always less than $e$.
youYou want to determine if $(\frac{101}{100})^{100}\geq 100$. But we know that $(1+\frac{1}{n})^n$$ \left(1+\frac{1}{n}\right)^n$ is always less than $e$.
you want to determine if $(\frac{101}{100})^{100}\geq 100$. But we know that $(1+\frac{1}{n})^n$ is always less than $e$.
You want to determine if $(\frac{101}{100})^{100}\geq 100$. But we know that $ \left(1+\frac{1}{n}\right)^n$ is always less than $e$.
