Timeline for About Birthday problem: Counting the configurations where people share birthday instead of configurations where people do not share brithday!
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Sep 14, 2017 at 1:50 | comment | added | YOUSEFY | Now, it is clear! Great answer! I did not consider such an event in my head! I should consider that. | |
| Sep 14, 2017 at 1:47 | vote | accept | YOUSEFY | ||
| Sep 13, 2017 at 18:53 | comment | added | Henry | @YOUSEFY You asked why your two calculations showed slightly different results. I showed that the difference is the probability of 3/4 sharing a birthday or of 4/4 sharing a birthday | |
| Sep 13, 2017 at 8:36 | comment | added | YOUSEFY | Thank you for answering! But I don't understand exactly your answer. Let me explain. We have 4 people. therefore, we are asked whether we have two people share the same birthday or not. thus, we have in this case one pair and the rest are different birthday or two pair and the rest is 0. So, take the sume is the probability that we have 2 people share the same birthday. In your answer: I don't understand why you consider 3 out of 4 people! | |
| Sep 13, 2017 at 8:15 | history | answered | Henry | CC BY-SA 3.0 |