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Jun 13, 2017 at 14:37 history closed amWhy
Leucippus
Claude Leibovici
hardmath
user91500
Duplicate of Incremental averaging
Jun 13, 2017 at 13:15 comment added hardmath Note that the first expression ("If I know the number of samples") has a sum of $n+1$ terms in the numerator but divides by $n$ in the denominator.
Jun 12, 2017 at 15:19 review Close votes
Jun 13, 2017 at 14:37
Jun 12, 2017 at 13:42 comment added Brydon Gibson Incremental averages was what I was looking for, I didn't know what it was called. Thank you.
Jun 12, 2017 at 13:29 comment added Dando18 are you asking how to find incremental averages?
Jun 12, 2017 at 13:29 comment added Ethan Bolker You can't do this without some information other than the average so far Related (from a search for running weighted average): stackoverflow.com/questions/9915653/…
Jun 12, 2017 at 13:25 history asked Brydon Gibson CC BY-SA 3.0