Timeline for How many 7-card hands can be dealt having exactly 3 of a kind?
Current License: CC BY-SA 3.0
18 events
| when toggle format | what | by | license | comment | |
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| Jul 25, 2018 at 18:32 | answer | added | ABBA | timeline score: 0 | |
| Feb 22, 2017 at 3:41 | vote | accept | Leanne | ||
| Feb 22, 2017 at 2:58 | history | edited | Leanne | CC BY-SA 3.0 |
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| Feb 22, 2017 at 2:57 | answer | added | user49640 | timeline score: 0 | |
| Feb 22, 2017 at 2:56 | history | edited | Leanne | CC BY-SA 3.0 |
added 308 characters in body
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| Feb 22, 2017 at 2:53 | comment | added | Leanne | This was the exact wording I was given, and I was a little confused by it as well. I think I see what some of you are saying about over-counting with the possibility of more than one 3-of-a-kind. I'm not sure how to edit my answer to include reasoning, but it went something like this: I first took into account the 13 choices for rank of the 3-of-a-kind, then found the combinations of choosing 3 cards from 4 in a rank, then, using the 48 cards left after removing the 4 cards from the rank of the 3-of-a-kind, I found the combinations of selecting the remaining four cards. | |
| Feb 22, 2017 at 2:41 | answer | added | Graham Kemp | timeline score: 1 | |
| Feb 22, 2017 at 2:37 | comment | added | lulu | Just to say: I interpret the problem to be "count the number of $7$ card hands which contain three of some rank, but not four of that rank, and no other duplicated ranks." I imagine the problem does not consider five card flushes, or five card straights. Of course, I might have it wrong. The OP should clarify. | |
| Feb 22, 2017 at 2:36 | history | edited | Harsh Kumar | CC BY-SA 3.0 |
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| Feb 22, 2017 at 2:33 | comment | added | Thomas Andrews | You have to be specific about what you mean by "exactly 3 of a kind." Do you mean that the best poker hand you have is "3 of a kind?" Or are you allowed to have a flush, or a full house? | |
| Feb 22, 2017 at 2:27 | review | Low quality posts | |||
| Feb 22, 2017 at 2:36 | |||||
| Feb 22, 2017 at 2:26 | comment | added | user49640 | What does this mean? Three cards with the same face value and then four more which all have different face values from each other and from the three of a kind? | |
| Feb 22, 2017 at 2:23 | comment | added | JMoravitz | in the unusual interpretation of two three-of-a-kinds being allowed (which i don't think it should be) you will have overcounted as well with this | |
| Feb 22, 2017 at 2:15 | history | edited | Alekos Robotis | CC BY-SA 3.0 |
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| Feb 22, 2017 at 2:15 | comment | added | The Count | How did you get this answer? Also, please put the question into the main text itself, and show us the logic behind the answer. | |
| Feb 22, 2017 at 2:12 | review | First posts | |||
| Feb 22, 2017 at 2:15 | |||||
| Feb 22, 2017 at 2:11 | comment | added | lulu | Doesn't look right....you choose three of a kind, yes, but then you choose four cards randomly (not matching the rank you previously selected). But if you started with $3$ Aces, the four cards you draw might all be Kings! You need to specify that the four cards you draw all have different ranks. | |
| Feb 22, 2017 at 2:09 | history | asked | Leanne | CC BY-SA 3.0 |