Timeline for Other Idea to show an inequality $\dfrac{1}{\sqrt 1}+\dfrac{1}{\sqrt 2}+\dfrac{1}{\sqrt 3}+\cdots+\dfrac{1}{\sqrt n}\geq \sqrt n$
Current License: CC BY-SA 3.0
4 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| May 27, 2017 at 15:03 | vote | accept | Khosrotash | ||
| Feb 20, 2017 at 0:29 | comment | added | rtybase | @zwim as long as it works | |
| Feb 20, 2017 at 0:21 | comment | added | zwim | That's kind of perverse to use $\sqrt k\le\sqrt n$ to get $n\sqrt n$ and not use it for $\frac{1}{\sqrt k}\ge\frac{1}{\sqrt n}$ as in Khosrotash solution. | |
| Feb 18, 2017 at 17:19 | history | answered | rtybase | CC BY-SA 3.0 |