Timeline for Other Idea to show an inequality $\dfrac{1}{\sqrt 1}+\dfrac{1}{\sqrt 2}+\dfrac{1}{\sqrt 3}+\cdots+\dfrac{1}{\sqrt n}\geq \sqrt n$
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jan 25, 2020 at 18:14 | comment | added | Klangen | Great answer! +1 | |
| Sep 1, 2017 at 3:48 | history | edited | Khosrotash | CC BY-SA 3.0 |
improve formatting
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| Apr 4, 2017 at 18:30 | comment | added | Stella Biderman | For an alternative interpretation of the same concept, divide by $n$ and observe that the LHS is the mean value and the RHS is the minimum value of the function $f(x)=1/\sqrt{x}$ on $[n]$ | |
| Feb 20, 2017 at 21:31 | audit | First posts | |||
| Feb 20, 2017 at 21:31 | |||||
| Feb 18, 2017 at 0:09 | history | answered | Khosrotash | CC BY-SA 3.0 |