Timeline for From a point $P$ outside a circle draw two tangents
Current License: CC BY-SA 3.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Feb 5, 2017 at 4:30 | comment | added | Mick | @NeWtoN $\angle purple1 = \angle BAP (= \angle green + \angle red)$ because they (purple1 and BAP) are both complement to $\angle OAB$. | |
| Feb 5, 2017 at 2:27 | comment | added | pi-π | you said,, $\angle purple 1=\angle green +\angle red$ but there are different angles colored green. Which one are you considering.? | |
| Feb 5, 2017 at 1:33 | comment | added | pi-π | Ok..for sure. You may try | |
| Feb 4, 2017 at 19:32 | comment | added | Mick | @NeWtoN I'll try but I haven't seen this type of question before. | |
| Feb 4, 2017 at 16:37 | comment | added | pi-π | @@Thanks mick,, could you please help me with this question too.. math.stackexchange.com/questions/2128331/… | |
| Feb 4, 2017 at 16:36 | vote | accept | pi-π | ||
| Feb 4, 2017 at 16:27 | comment | added | Mick | @NeWtoN The two reds are equal because of "angle in alternate segment". The equality of the greens can be deduced the same way. the purples are equal because of "tangent properties". | |
| Feb 4, 2017 at 16:18 | comment | added | pi-π | why are those angles (same colored) equal? | |
| Feb 4, 2017 at 16:15 | history | edited | Mick | CC BY-SA 3.0 |
deleted 15 characters in body
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| Feb 4, 2017 at 16:10 | history | answered | Mick | CC BY-SA 3.0 |