Timeline for How does a mathematician create a new zeta function?
Current License: CC BY-SA 3.0
26 events
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| Jan 14, 2017 at 21:35 | comment | added | user243301 | @TheGreatDuck then you are right. In Wikipedia there is an entry List of zeta functions, my purpose was provide my viewpoint. I don't know very well what's a zeta function. | |
| Jan 14, 2017 at 8:58 | comment | added | user243301 | I am saying the first paragraphs, that are the formula (6) and the comment in italic, in page 4 of Flajolet and Gourdon and Dumas, Mellin Transforms and Asymptotics: Harmonic sums. Then I undersand (and I don't know this theory) that if you know how compute the Mellin transfor, of $G(x)$ and $g(x)$ you can define implicitement a zeta function using the formula (6). I try force me to study these tools because I believe that are modern tools. Many thanks for your attention @TheGreatDuck | |
| Jan 7, 2017 at 22:41 | comment | added | Simply Beautiful Art | If I may, I have updated my answer... | |
| Jan 2, 2017 at 10:17 | comment | added | user243301 | How does a mathematician create a new zeta function? I believe that also is possible using a property of the Mellin transform, when is applied to an harmonic series. | |
| Jan 1, 2017 at 19:42 | vote | accept | user3141592 | ||
| S Jan 1, 2017 at 19:13 | history | suggested | jwodder | CC BY-SA 3.0 |
Proofreading
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| Jan 1, 2017 at 19:06 | review | Suggested edits | |||
| S Jan 1, 2017 at 19:13 | |||||
| Jan 1, 2017 at 16:38 | comment | added | Simply Beautiful Art | Aha! I done did it! Closed form solution for arbitrary $s\in\mathbb N$ is given below now. | |
| Jan 1, 2017 at 15:16 | vote | accept | user3141592 | ||
| Jan 1, 2017 at 19:42 | |||||
| Jan 1, 2017 at 15:14 | comment | added | user3141592 | @user1952009 I had changed it before your answer was posted | |
| Jan 1, 2017 at 15:11 | answer | added | Gerry Myerson | timeline score: 5 | |
| Jan 1, 2017 at 15:09 | comment | added | user3141592 | @user1952009 It was not me the one who changed it the last times. Stop making noise please | |
| Jan 1, 2017 at 15:01 | answer | added | Simply Beautiful Art | timeline score: 13 | |
| Jan 1, 2017 at 14:50 | comment | added | Simply Beautiful Art | @user1952009 That would definitely explain a few things. | |
| Jan 1, 2017 at 14:50 | comment | added | reuns | @SimpleArt he changed his function 3 times. And WA is very bad with Dirichlet series | |
| Jan 1, 2017 at 14:48 | comment | added | Simply Beautiful Art | @user3141592 What is similar between this and the Prime zeta function? I've already looked at this, and so has WolframAlpha. AFAIK, this function is not known in terms of other special functions. | |
| Jan 1, 2017 at 14:40 | answer | added | goblin GONE | timeline score: 3 | |
| Jan 1, 2017 at 14:22 | history | edited | reuns | CC BY-SA 3.0 |
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| Jan 1, 2017 at 14:16 | answer | added | reuns | timeline score: 5 | |
| Jan 1, 2017 at 14:06 | comment | added | user3141592 | @GEdgar Why? I mean, this function seems very similar to the Prime Zeta Function. And if we cannot use the same method, how would we analyse it? | |
| Jan 1, 2017 at 14:02 | comment | added | GEdgar | Most functions do not work the same way Riemann's did. So they will need different methods than Riemann used. A few functions do have properties so much like Riemann's that they are called "zeta functions," but I am afraid yours is not one of them. | |
| Jan 1, 2017 at 13:59 | history | edited | user3141592 | CC BY-SA 3.0 |
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| Jan 1, 2017 at 13:52 | history | edited | user3141592 | CC BY-SA 3.0 |
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| Jan 1, 2017 at 13:51 | comment | added | user3141592 | @mathbeing Nope. My aim there was to create a new function not studied before, to see the method used to analyse any totally new function | |
| Jan 1, 2017 at 13:40 | comment | added | user378947 | Maybe you meant $n^\alpha$ instead of $n^2$ in the definition of the "zeta function above. ? | |
| Jan 1, 2017 at 13:35 | history | asked | user3141592 | CC BY-SA 3.0 |