Timeline for Prove $4-\sqrt{2}-\sqrt[3]{3}-\sqrt[5]{5} \gt 0$
Current License: CC BY-SA 3.0
17 events
| when toggle format | what | by | license | comment | |
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| Dec 30, 2016 at 19:49 | comment | added | Jack D'Aurizio | Or $$12\cdot 2^{1/2}+9\cdot 3^{1/3}-21\cdot 5^{1/5} \stackrel{?}{<} 1.$$ | |
| Dec 30, 2016 at 19:24 | vote | accept | pasaba por aqui | ||
| S Dec 30, 2016 at 18:58 | history | edited | amWhy |
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| Dec 30, 2016 at 18:50 | comment | added | Robert Israel | For a harder one, you might try $7-20\,\sqrt {2}+2\,\sqrt [3]{3}-\sqrt [5]{5}-\sqrt [6]{6}+16\,\sqrt [7 ]{7} $. | |
| Dec 30, 2016 at 18:47 | comment | added | marwalix | The title is wrong because $4-\sqrt{2}-\sqrt[3]{3}-\sqrt[5]{5}\lt 0$ | |
| Dec 30, 2016 at 18:45 | review | Suggested edits | |||
| S Dec 30, 2016 at 18:58 | |||||
| Dec 30, 2016 at 18:45 | answer | added | Sil | timeline score: 24 | |
| S Dec 30, 2016 at 18:44 | history | suggested | pseudoeuclidean | CC BY-SA 3.0 |
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| Dec 30, 2016 at 18:44 | comment | added | George Law | @pasabaporaqui Okay. But now you want to disprove it rather than prove it. | |
| Dec 30, 2016 at 18:42 | comment | added | pasaba por aqui | @George Law: it doesn't matter, the issue is find a method to say "yes, it is greater" or "no". First number (and, in fact, all remainders) are only examples. | |
| Dec 30, 2016 at 18:41 | comment | added | George Law | @pasabaporaqui You originally wrote $5-\sqrt2-\sqrt[3]3-\sqrt[5]5>0$ which was correct. | |
| Dec 30, 2016 at 18:39 | comment | added | Mark Bennet | In principle, either way, it should be possible to obtain close-enough rational approximations of the roots. | |
| Dec 30, 2016 at 18:39 | comment | added | pasaba por aqui | sorry, I do not understand. What is wrong? (the proof can result in "no") | |
| Dec 30, 2016 at 18:38 | review | Suggested edits | |||
| S Dec 30, 2016 at 18:44 | |||||
| Dec 30, 2016 at 18:38 | comment | added | George Law | The original title was correct; now it's wrong. | |
| Dec 30, 2016 at 18:37 | history | edited | pasaba por aqui | CC BY-SA 3.0 |
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| Dec 30, 2016 at 18:35 | history | asked | pasaba por aqui | CC BY-SA 3.0 |