1. How many eight-card hands can be chosen from exactly 2 suits of an ordinary 52-card deck? (there are 4 suits clubs, diamonds, hearts and spades

I think since there are 26 cards in 2 suits and eight cards from those 26 (order does not matter), thus $C(26,8)/C(52,26)$ ?

2. How many 13-card bridge hands can be chosen from an ordinary 52-card deck that contain six cards of one suit and four and three cards of another two suits? (there are 4 suits clubs, diamonds, hearts and spades

I do not understand 2nd problem.

1. How many eight-card hands can be chosen from exactly $2$ suits of an ordinary $52$-card deck? (there are $4$ suits clubs, diamonds, hearts and spades

I think since there are $26$ cards in $2$ suits and eight cards from those $26$ (order does not matter), thus $\displaystyle\frac{\binom{26}{8}}{\binom{52}{26}}$ ?

2. How many $13$-card bridge hands can be chosen from an ordinary $52$-card deck that contain six cards of one suit and four and three cards of another two suits? (there are $4$ suits clubs, diamonds, hearts and spades

I do not understand $2$nd problem.