Skip to main content
Mathematics

Return to Answer

deleted 95 characters in body
Source Link
Mario Ishac
Mario Ishac
  • 225
  • 2
  • 11

We are comparing $202^{303}$ and $303^{202}$.

$202^{303}$ is equal to $202^{202}$ * $202^{101}$.

$303^{202}$ is equal to $(202 * 1.5)^{202}$ which is equal to $202^{202}$ * $1.5^{202}$

Now, we can divide out the $202^{202}$ from both sides which yields $202^{101}$ versus $1.5^{202}$. $1.5^{202}$ can be written as $2.25^{101}$ (squaring the inside, thus dividing the exponent by 2). Since $202^{101}$ > $2.25^{101}$, $202^{303}$ > $303^{202}$. No need for calculus!

Please tell me if my answer can be improved upon, my very first answer in this community :)

We are comparing $202^{303}$ and $303^{202}$.

$202^{303}$ is equal to $202^{202}$ * $202^{101}$.

$303^{202}$ is equal to $(202 * 1.5)^{202}$ which is equal to $202^{202}$ * $1.5^{202}$

Now, we can divide out the $202^{202}$ from both sides which yields $202^{101}$ versus $1.5^{202}$. $1.5^{202}$ can be written as $2.25^{101}$ (squaring the inside, thus dividing the exponent by 2). Since $202^{101}$ > $2.25^{101}$, $202^{303}$ > $303^{202}$. No need for calculus!

Please tell me if my answer can be improved upon, my very first answer in this community :)

We are comparing $202^{303}$ and $303^{202}$.

$202^{303}$ is equal to $202^{202}$ * $202^{101}$.

$303^{202}$ is equal to $(202 * 1.5)^{202}$ which is equal to $202^{202}$ * $1.5^{202}$

Now, we can divide out the $202^{202}$ from both sides which yields $202^{101}$ versus $1.5^{202}$. $1.5^{202}$ can be written as $2.25^{101}$ (squaring the inside, thus dividing the exponent by 2). Since $202^{101}$ > $2.25^{101}$, $202^{303}$ > $303^{202}$. No need for calculus!

added 2 characters in body
Source Link
Mario Ishac
Mario Ishac
  • 225
  • 2
  • 11

We are comparing $202^{303}$ and $303^{202}$.

$202^{303}$ is equal to $202^{202}$ * $202^{101}$.

$303^{202}$ is equal to $(202 * 1.5)^{202}$ which is equal to $202^{202}$ * $1.5^{202}$

Now, we can subtractdivide out the $202^{202}$ from both sides which yields $202^{101}$ versus $1.5^{202}$. $1.5^{202}$ can be written as $2.25^{101}$ (squaring the inside, thus dividing the exponent by 2). Since $202^{101}$ > $2.25^{101}$, $202^{303}$ > $303^{202}$. No need for calculus!

Please tell me if my answer can be improved upon, my very first answer in this community :)

We are comparing $202^{303}$ and $303^{202}$.

$202^{303}$ is equal to $202^{202}$ * $202^{101}$.

$303^{202}$ is equal to $(202 * 1.5)^{202}$ which is equal to $202^{202}$ * $1.5^{202}$

Now, we can subtract the $202^{202}$ from both sides which yields $202^{101}$ versus $1.5^{202}$. $1.5^{202}$ can be written as $2.25^{101}$ (squaring the inside, thus dividing the exponent by 2). Since $202^{101}$ > $2.25^{101}$, $202^{303}$ > $303^{202}$. No need for calculus!

Please tell me if my answer can be improved upon, my very first answer in this community :)

We are comparing $202^{303}$ and $303^{202}$.

$202^{303}$ is equal to $202^{202}$ * $202^{101}$.

$303^{202}$ is equal to $(202 * 1.5)^{202}$ which is equal to $202^{202}$ * $1.5^{202}$

Now, we can divide out the $202^{202}$ from both sides which yields $202^{101}$ versus $1.5^{202}$. $1.5^{202}$ can be written as $2.25^{101}$ (squaring the inside, thus dividing the exponent by 2). Since $202^{101}$ > $2.25^{101}$, $202^{303}$ > $303^{202}$. No need for calculus!

Please tell me if my answer can be improved upon, my very first answer in this community :)

Source Link
Mario Ishac
Mario Ishac
  • 225
  • 2
  • 11

We are comparing $202^{303}$ and $303^{202}$.

$202^{303}$ is equal to $202^{202}$ * $202^{101}$.

$303^{202}$ is equal to $(202 * 1.5)^{202}$ which is equal to $202^{202}$ * $1.5^{202}$

Now, we can subtract the $202^{202}$ from both sides which yields $202^{101}$ versus $1.5^{202}$. $1.5^{202}$ can be written as $2.25^{101}$ (squaring the inside, thus dividing the exponent by 2). Since $202^{101}$ > $2.25^{101}$, $202^{303}$ > $303^{202}$. No need for calculus!

Please tell me if my answer can be improved upon, my very first answer in this community :)