Timeline for Show that $ \lim\limits_{n\to\infty}\frac{1}{n}\sum\limits_{k=0}^{n-1}e^{ik^2}=0$
Current License: CC BY-SA 3.0
28 events
| when toggle format | what | by | license | comment | |
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| Oct 27, 2016 at 13:05 | history | edited | Renart |
edited tags
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| S Feb 13, 2016 at 15:48 | history | bounty ended | Renart | ||
| S Feb 13, 2016 at 15:48 | history | notice removed | Renart | ||
| Feb 13, 2016 at 15:47 | vote | accept | Renart | ||
| Feb 11, 2016 at 22:34 | comment | added | user198044 | @Renart Which one? | |
| Feb 8, 2016 at 16:50 | answer | added | Sean Eberhard | timeline score: 15 | |
| S Feb 8, 2016 at 13:24 | history | bounty started | Renart | ||
| S Feb 8, 2016 at 13:24 | history | notice added | Renart | Draw attention | |
| Feb 8, 2016 at 12:41 | history | edited | Renart | CC BY-SA 3.0 |
added 488 characters in body
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| Feb 5, 2016 at 10:09 | comment | added | Renart | @Jack Bauer stolz cesaro doesn't apply because the hypothesis of the theorem are not satified... | |
| Feb 5, 2016 at 5:53 | history | tweeted | twitter.com/StackMath/status/695485490234052609 | ||
| Feb 4, 2016 at 23:24 | comment | added | tired | @JackBauer the remainder is unbounded | |
| Feb 4, 2016 at 14:54 | comment | added | user198044 | @Renart Why doesn't it apply here? | |
| Feb 3, 2016 at 12:57 | comment | added | tired | i mean $\frac{\sum}{n}$ | |
| Feb 3, 2016 at 12:56 | comment | added | Renart | You probably made a mistake : the integral is convergent (because integral of cos(x^2) and sin(x^2) are convergent) but the sum isn't. | |
| Feb 3, 2016 at 12:46 | comment | added | tired | @Renart that was also the conclusion that i obtained. But interestinglz the difference between sum and integral seems to go to zero (numerically), so maybe we miss something here\ | |
| Feb 3, 2016 at 11:11 | comment | added | Renart | Okay Euler Maclaurin isn't usefull here. I didn't obtained usefull bounds and i'm even pretty sure that the series and the remainder appearing in the E-M formulae are divergent. | |
| Feb 2, 2016 at 22:07 | comment | added | Renart | Stolz–Cesàro theorem doesn't apply here. I'll try tomorow for Euleur Mac-Laurin but formulaes seems a little nasty. (definitely worth the try though) | |
| Feb 2, 2016 at 21:59 | history | edited | Renart | CC BY-SA 3.0 |
The use of mathbf over mathbb is not a typo, it's a pretty common convention, used for example, in Rudin's book (and remember that "bb" stands for "Blackboard Bold"). But thanks for the other typos !
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| Feb 2, 2016 at 21:16 | history | edited | Winther | CC BY-SA 3.0 |
fixed some typos
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| Feb 2, 2016 at 17:54 | comment | added | tired | i would guess that Euler Mac-Laurin could be working here | |
| S Feb 2, 2016 at 17:52 | history | suggested | user153330 | CC BY-SA 3.0 |
displaystyle prohibited in title
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| Feb 2, 2016 at 17:48 | comment | added | user198044 | What's wrong with this one? en.wikipedia.org/wiki/Stolz%E2%80%93Ces%C3%A0ro_theorem | |
| Feb 2, 2016 at 17:37 | comment | added | user153330 | great question @Renart (+1) | |
| Feb 2, 2016 at 17:37 | review | Suggested edits | |||
| S Feb 2, 2016 at 17:52 | |||||
| Feb 2, 2016 at 17:31 | comment | added | Renart | i don't think i understand your question | |
| Feb 2, 2016 at 17:30 | comment | added | Eric Towers | You want to know when a (potentially open) polygon with unit edges, with directions given by the quadratic residues $\pmod n$ is closed? | |
| Feb 2, 2016 at 17:27 | history | asked | Renart | CC BY-SA 3.0 |