Timeline for Why does an argument similiar to 0.999...=1 show 999...=-1?
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Jan 26, 2016 at 16:33 | comment | added | Paul Sinclair | The proof is entirely valid in the 10-adic numbers, which form a quite interesting ring. Addition and multiplication in the 10-adics are associative and commutive. $0$ and $1$ are still identities, and additive inverses still exist. Multiplicative inverses exist if the number is not a 0-divisor, but there are some 0-divisors. This only becomes absurd if someone demands that these be considered real numbers. | |
Jan 26, 2016 at 0:06 | history | answered | Joshua | CC BY-SA 3.0 |