Timeline for What is the largest prime number in the denominator of a fraction that creates a decimal that repeats every 4 digits?
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jan 14, 2016 at 1:38 | vote | accept | CaptainObvious | ||
| Jan 14, 2016 at 1:12 | comment | added | David | @vonbrand My last statement concerns the case when $101\not\mid q$. The fractions in your comment are irrelevant. | |
| Jan 14, 2016 at 1:09 | comment | added | David | @CaptainObvious This is just the working you have already done in your question,$$9999\frac pq=10000\frac pq-\frac pq=abcd\mathord\cdot abcd\cdots-0\mathord\cdot abcd\cdots=abcd\ .$$ | |
| Jan 14, 2016 at 1:07 | comment | added | CaptainObvious | Can you clarify the $9999p=[abcd]q$ part for me? I'm a high school student. | |
| Jan 14, 2016 at 1:07 | comment | added | user304329 | I don't see how this is wrong. His last statement is about when 101 is not a divisor of $q$, so that is also correct. | |
| Jan 14, 2016 at 1:06 | comment | added | vonbrand | They don't have repeat $[abab]$ as you state. | |
| Jan 14, 2016 at 1:03 | comment | added | David | @vonbrand What exactly is wrong? Are you saying that $101$ is not a factor of the denominators of your fractions? | |
| Jan 14, 2016 at 1:00 | comment | added | vonbrand | Wrong. $1/101 = 0.0099009900\ldots$, $2/101 = 0.019801980\ldots$. | |
| Jan 14, 2016 at 0:41 | history | answered | David | CC BY-SA 3.0 |