Timeline for Probability of 4th card drawn to be a king?
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 11, 2019 at 19:59 | answer | added | BobKnobsky | timeline score: 1 | |
| Dec 29, 2016 at 17:13 | answer | added | Quasar | timeline score: 0 | |
| Sep 25, 2015 at 22:50 | answer | added | GarryB | timeline score: 0 | |
| Sep 25, 2015 at 18:45 | answer | added | user265328 | timeline score: 3 | |
| Sep 25, 2015 at 18:39 | answer | added | Christian Blatter | timeline score: 3 | |
| Sep 25, 2015 at 18:19 | comment | added | André Nicolas | One can also do it the long way. There is a King in fourth place if we draw non-Kings $3$ times and then a King. Or if we draw one King and two non-Kings in the first three draws, and then a King. And so on. Calculate, add up, simplify. You will get (if there is no error) $1/13$. Good exercise, great incentive to solve the simple way. | |
| Sep 25, 2015 at 18:15 | comment | added | André Nicolas | The probability is indeed $4/52$. The probability there is a king in fourth place, or $47$-th place, is the same as the probability there is a king in first place. | |
| Sep 25, 2015 at 18:10 | history | asked | user2409011 | CC BY-SA 3.0 |