Timeline for Proof that the factorial is nonelementary
Current License: CC BY-SA 3.0
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Mar 29, 2021 at 15:47 | comment | added | Anixx | @Davey Bernoulli numbers as function of the order are essentially, zeta function. | |
Mar 29, 2021 at 15:45 | comment | added | Anixx | Then you should prove that Hurwitz Zeta is non-elementary. | |
Jun 12, 2020 at 10:38 | history | edited | CommunityBot |
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May 14, 2020 at 4:03 | comment | added | Davey | This does not quite make sense to me: each individual Bernoulli polynomial $B_n(x)$ is of course elementary, but why is $B_n = B_n(0)$ elementary as a function of $n$? If it is, then what's a closed form expression for it? We can't use a series that involves binomial coefficients since I'm pretty sure those aren't elementary (they seem strictly more complicated than the factorial function, right?).I don't think we can even say that IF the factorial is elementary, then $B_n$ is elementary. | |
Sep 24, 2016 at 11:18 | history | edited | Vincenzo Oliva | CC BY-SA 3.0 |
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Aug 13, 2015 at 19:37 | comment | added | Vincenzo Oliva | @Dave: Nice, thank you. And +1, by the way. | |
Aug 13, 2015 at 19:32 | comment | added | Dave L. Renfro | In fact, the gamma function doesn't even satisfy an algebraic differential equation -- see Expanded concept of elementary function?. | |
Aug 13, 2015 at 19:19 | history | edited | Vincenzo Oliva | CC BY-SA 3.0 |
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Aug 13, 2015 at 19:13 | comment | added | Vincenzo Oliva | In fact there's no need of seeking for a contradiction, to prove Claim 2. | |
Aug 13, 2015 at 19:13 | history | edited | Vincenzo Oliva | CC BY-SA 3.0 |
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Aug 12, 2015 at 9:10 | vote | accept | Akiva Weinberger | ||
Aug 12, 2015 at 8:55 | history | edited | Vincenzo Oliva | CC BY-SA 3.0 |
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Aug 12, 2015 at 8:28 | history | edited | Vincenzo Oliva | CC BY-SA 3.0 |
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Aug 12, 2015 at 8:02 | history | edited | Vincenzo Oliva | CC BY-SA 3.0 |
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Aug 12, 2015 at 7:54 | history | edited | Vincenzo Oliva | CC BY-SA 3.0 |
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Aug 12, 2015 at 7:45 | history | answered | Vincenzo Oliva | CC BY-SA 3.0 |