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May 11, 2015 at 1:54 comment added rondo9 This is a really good question to ask!
May 11, 2015 at 1:18 answer added Qiaochu Yuan timeline score: 4
May 10, 2015 at 20:01 comment added Priyanshu Thanks Lucian! I understand the issue with the proof now.
May 10, 2015 at 19:50 comment added Priyanshu Thanks Matt. Well I would have appreciated a more mathematical explanation of what exactly is wrong with what I mentioned. I'm totally convinced that the set of rational numbers is countably infinte and that the set of real numbers is not.
May 10, 2015 at 19:49 comment added Lucian each number on the list has a finite length - Not all rationals have finite length.
May 10, 2015 at 19:13 comment added Matt Samuel It's not possible to fix the proof because what you are trying to prove is not true. I promise nobody has been lying to you, the rationals are countably infinite and hence can be written in a list, but the set of reals is uncountable and cannot.
May 10, 2015 at 19:06 comment added Priyanshu Thanks Daniel! Is it possible to address this by explicitly stating that each number on the list has non-zero digits till the $n^{th}$ place beyond which it can simply be appended with zeros i.e. each number on the list has a finite length. Not sure if this would lead to another flaw in the proof.
May 10, 2015 at 18:50 comment added Daniel Fischer You don't know that the number you constructed is rational.
May 10, 2015 at 18:49 history asked Priyanshu CC BY-SA 3.0