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In the 4th case, it does matter which is the first and which is the second suit.
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wythagoras
wythagoras
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I think it should be C(13,6)C(4,2)C(13,6)C(26,1), since the second suit must be different from the first. Other than that, it looks fine to me.

I think your tutors answer doesn't require the suits form the sextuples to be different, and it doens't require the extra card to be form a different suit than the sextuples. However, than the correct answer is:

$$C(13,12)C(4,1)C(39,1)+ C(13,13)C(4,1)+ C(4,1)C(13,6)C(3,1)C(13,6)C(26,1)+ C(4,1)C(13,7)C(3,1)C(13,6)$$$$C(13,12)C(4,1)C(39,1)+ C(13,13)C(4,1)+ C(4,2)C(13,6)C(13,6)C(26,1)+ C(4,1)C(3,1)C(13,7)C(13,6)$$

So you should ask your tutor about the exact conditions for this problem.

I think it should be C(13,6)C(4,2)C(13,6)C(26,1), since the second suit must be different from the first. Other than that, it looks fine to me.

I think your tutors answer doesn't require the suits form the sextuples to be different, and it doens't require the extra card to be form a different suit than the sextuples. However, than the correct answer is:

$$C(13,12)C(4,1)C(39,1)+ C(13,13)C(4,1)+ C(4,1)C(13,6)C(3,1)C(13,6)C(26,1)+ C(4,1)C(13,7)C(3,1)C(13,6)$$

So you should ask your tutor about the exact conditions for this problem.

I think it should be C(13,6)C(4,2)C(13,6)C(26,1), since the second suit must be different from the first. Other than that, it looks fine to me.

I think your tutors answer doesn't require the suits form the sextuples to be different, and it doens't require the extra card to be form a different suit than the sextuples. However, than the correct answer is:

$$C(13,12)C(4,1)C(39,1)+ C(13,13)C(4,1)+ C(4,2)C(13,6)C(13,6)C(26,1)+ C(4,1)C(3,1)C(13,7)C(13,6)$$

So you should ask your tutor about the exact conditions for this problem.

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wythagoras
wythagoras
  • 25.3k
  • 6
  • 61
  • 113

I think it should be C(13,6)C(4,12)C(13,6)C(3,1)C(26,1), since the second suit must be different from the first. Other than that, it looks fine to me.

I think your tutors answer doesn't require the suits form the sextuples to be different, and it doens't require the extra card to be form a different suit than the sextuples. However, than the correct answer is:

$$C(13,12)C(4,1)C(39,1)+ C(13,13)C(4,1)+ C(4,1)C(13,6)C(3,1)C(13,6)C(26,1)+ C(4,1)C(13,7)C(3,1)C(13,6)$$

So you should ask your tutor about the exact conditions for this problem.

I think it should be C(13,6)C(4,1)C(13,6)C(3,1)C(26,1), since the second suit must be different from the first. Other than that, it looks fine to me.

I think your tutors answer doesn't require the suits form the sextuples to be different, and it doens't require the extra card to be form a different suit than the sextuples. However, than the correct answer is:

$$C(13,12)C(4,1)C(39,1)+ C(13,13)C(4,1)+ C(4,1)C(13,6)C(3,1)C(13,6)C(26,1)+ C(4,1)C(13,7)C(3,1)C(13,6)$$

So you should ask your tutor about the exact conditions for this problem.

I think it should be C(13,6)C(4,2)C(13,6)C(26,1), since the second suit must be different from the first. Other than that, it looks fine to me.

I think your tutors answer doesn't require the suits form the sextuples to be different, and it doens't require the extra card to be form a different suit than the sextuples. However, than the correct answer is:

$$C(13,12)C(4,1)C(39,1)+ C(13,13)C(4,1)+ C(4,1)C(13,6)C(3,1)C(13,6)C(26,1)+ C(4,1)C(13,7)C(3,1)C(13,6)$$

So you should ask your tutor about the exact conditions for this problem.

added 324 characters in body
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wythagoras
wythagoras
  • 25.3k
  • 6
  • 61
  • 113

I think it should be C(13,6)C(4,1)C(13,6)C(3,1)C(26,1), since the second suit must be different from the first. Other than that, it looks fine to me.

I think your tutors answer doesn't require the suits form the sextuples to be different, and it doens't require the extra card to be form a different suit than the sextuples. However, than the correct answer is:

$$C(13,12)C(4,1)C(39,1)+ C(13,13)C(4,1)+ C(4,1)C(13,6)C(3,1)C(13,6)C(26,1)+ C(4,1)C(13,7)C(3,1)C(13,6)$$

So you should ask your tutor about the exact conditions for this problem.

I think it should be C(13,6)C(4,1)C(13,6)C(3,1)C(26,1), since the second suit must be different from the first. Other than that, it looks fine to me.

I think it should be C(13,6)C(4,1)C(13,6)C(3,1)C(26,1), since the second suit must be different from the first. Other than that, it looks fine to me.

I think your tutors answer doesn't require the suits form the sextuples to be different, and it doens't require the extra card to be form a different suit than the sextuples. However, than the correct answer is:

$$C(13,12)C(4,1)C(39,1)+ C(13,13)C(4,1)+ C(4,1)C(13,6)C(3,1)C(13,6)C(26,1)+ C(4,1)C(13,7)C(3,1)C(13,6)$$

So you should ask your tutor about the exact conditions for this problem.

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wythagoras
wythagoras
  • 25.3k
  • 6
  • 61
  • 113