Timeline for Find All Dimensions such that Volume of Box = Surface Area
Current License: CC BY-SA 3.0
4 events
| when toggle format | what | by | license | comment | |
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| Mar 20, 2015 at 23:16 | comment | added | marty cohen | For the lower bound, if the expression ($4/(h-2)$) is an integer, then we want the next integer, since the inequality is strict. That's why I used floor + 1. | |
| Mar 20, 2015 at 21:57 | vote | accept | A is for Ambition | ||
| Apr 2, 2015 at 13:21 | |||||
| Mar 20, 2015 at 21:53 | comment | added | A is for Ambition | hi marty, great solution and thanks for introducing me to Egyptian fraction analysis :) i just have one question, though, which is why you used the floor function to define both the lower and upper bounds. thanks! | |
| Mar 20, 2015 at 19:49 | history | answered | marty cohen | CC BY-SA 3.0 |