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Nov 22, 2014 at 7:39 vote accept k99731
Nov 22, 2014 at 7:25 comment added k99731 Okay, i understand your approach. I guess you have wrong constants. for the coefficient of $\frac{1}{(z-1)^2}$, the $k $ should be 1. In fact, it is just finding taylor series for $(z-1)^3 f(x)$. But it is really helpful to me.
Nov 22, 2014 at 7:18 comment added k99731 you answer cannot give the negative sign..
Nov 21, 2014 at 13:39 history answered Nosrati CC BY-SA 3.0