How to UPDATE with LATERAL Nearest-Neighbour query?

Question

Say I have table gps like:

CREATE TABLE gps(
   gps_id serial primary key,
   measured_timestamp timestamp, 
   geom Geometry(Point,4326),
   stop_id int --Null
);

And I have a table of stops like:

CREATE TABLE stops(
   stop_id serial primary key,
   geom Geometry(Point,4326)
);

If I want to do an UPDATE on gps to find the nearest stop to each point, is there a way to use a LATERAL query?

I tried something like

UPDATE gps
SET stop_id = nearest.stop_id
FROM LATERAL(SELECT stop_id FROM stops ORDER BY stops.geom <-> gps.geom LIMIT 1) nearest

but that told me

ERROR:  invalid reference to FROM-clause entry for table "gps"
                                               ^
HINT:  There is an entry for table "gps", but it cannot be referenced from this part of the query.

So is the only way to do?

UPDATE gps
SET stop_id = nearest.stop_id
FROM (SELECT gps.gps_id, stop_id 
      FROM gps
      LATERAL JOIN (SELECT stop_id FROM stops ORDER BY stops.geom <-> gps.geom LIMIT 1) stops) nearest
WHERE nearest.gps_id = gps.gps_id

This feels like joining the same table to itself, which wouldn't need to happen with a SELECT INTO

Answer 1

No need for JOIN LATERAL (or do you really just want to use it?); an UPDATE will pass each processing row to the following query, which is the same concept as using a JOIN LATERAL.[*]

Try

UPDATE gps
  SET  stop_id = (
    SELECT stops.stop_id
    FROM   stops
    ORDER BY
           gps.geom <-> stops.geom
    LIMIT  1
  )
;

---

[*] Just to give an example on that; consider a SELECT instead to find the closest stop to each gps point using JOIN LATERAL:

SELECT a.gps_id,
       a.measured_timestamp,
       a.geom,
       b.stop_id
FROM   gps AS a
CROSS JOIN LATERAL (
  SELECT stops.stop_id
  FROM   stops
  ORDER BY
         a.geom <-> stops.geom
  LIMIT  1
) AS b
;

Each row in gps is now passed individually and subsequentially to the JOIN LATERAL sub-query to be processed; this (sort of) mimicks the UPDATE command (note how it is the same sub-query).

Answer 2

And if you want to store this minimal distance in your gps table you can use this code:

ALTER TABLE gps
ADD min_distance float8;

UPDATE gps
SET min_distance = list.distance
FROM(
    SELECT gps.gps_id AS name, MIN(gps.geom <-> stops.geom) AS distance
    FROM gps
    CROSS JOIN stops
    GROUP BY gps.gps_id
    ORDER BY gps.gps_id)
    AS list
WHERE gps.gps_id = list.name;