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1988 Tournament of the Americas

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1988 Tournament of the Americas
Tournament details
Host countryUruguay
Dates22–31 May
Teams7
Venue(s)1 (in 1 host city)
Final positions
Champions Brazil (2nd title)
Runners-up Puerto Rico
Third place Canada
Fourth place Uruguay
1984
1989

The 1988 Tournament of the Americas, later known as the FIBA Americas Championship and the FIBA AmeriCup, was a basketball championship hosted by Uruguay from 22 to 31 May 1988. The games were played in Montevideo. This FIBA AmeriCup was to earn the three berths allocated to the Americas for the 1988 Summer Olympics in Seoul. The United States did not participate in the tournament, as the team had already been awarded a berth in the Olympics. Brazil defeated Puerto Rico in the final to win the tournament.[1] Canada beat Uruguay in the third place game to claim the final Olympic berth.

Qualification

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Eight teams qualified during the qualification tournaments held in their respective zones in 1987; Canada qualified automatically since they are one of only two members of the North America zone. Panama and the Dominican Republic withdrew from the tournament. The teams formed a single group of seven teams.

Format

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  • The top four teams from the main group advance to the semifinals.
  • The winners in the knockout semifinals advanced to the Final and were granted berths in the 1988 Summer Olympics tournament in Seoul. The losers figure in a third-place playoff where the winner was given the third and final place in the Olympics.

Squads

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Preliminary round

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Qualified for the semifinals
Team Pld W L PF PA PD Pts
 Brazil 6 5 1 591 559 +32 11
 Puerto Rico 6 5 1 493 456 +37 11
 Canada 6 3 3 507 506 +1 9
 Uruguay 6 3 3 533 487 +46 9
 Argentina 6 3 3 533 567 −34 9
 Mexico 6 2 4 546 549 −3 8
 Venezuela 6 0 6 471 570 −99 6
22 May
Puerto Rico  80–63  Canada
22 May
Brazil  113–93  Argentina
22 May
Uruguay  100–67  Venezuela


23 May
Puerto Rico  94–81  Argentina
23 May
Uruguay  98–84  Mexico
23 May
Canada  94–88  Venezuela


24 May
Brazil  98–92  Puerto Rico
24 May
Canada  84–81  Mexico
24 May
Argentina  110–77  Venezuela


25 May
Uruguay  79–68  Canada
25 May
Argentina  91–89  Mexico
25 May
Brazil  91–83  Venezuela


26 May
Puerto Rico  65–63  Venezuela
26 May
Mexico  111–103  Brazil
26 May
Argentina  90–82  Uruguay


27 May
Puerto Rico  80–71  Mexico
27 May
Brazil  96–94  Uruguay
27 May
Canada  112–88  Argentina


28 May
Puerto Rico  82–80  Uruguay
28 May
Brazil  90–86  Canada
28 May
Mexico  110–93  Venezuela

Knockout stage

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Semi-finalsFinal
 
      
 
30 May
 
 
 Puerto Rico62
 
31 May
 
 Canada60
 
 Brazil101
 
30 May
 
 Puerto Rico92[1]
 
 Brazil90
 
 
 Uruguay83
 
Third place
 
 
31 May
 
 
 Canada87
 
 
 Uruguay80

Awards

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 1988 Tournament of the Americas winners 

Brazil
Second title

Final standings

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Qualified for the 1988 Olympic Tournament
Rank Team Record
1st place, gold medalist(s)  Brazil 7–1
2nd place, silver medalist(s)  Puerto Rico 6–2
3rd place, bronze medalist(s)  Canada 4–4
4  Uruguay 3–5
5  Argentina 3–3
6  Mexico 2–4
7  Venezuela 0–6

References

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  1. ^ a b "Brazil defeats P. R. for gold". The San Juan Star. 1988-06-01. Retrieved 2011-09-16.