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1894 Minnesota Senate election

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1894 Minnesota Senate election

← 1890 November 6, 1894 (1894-11-06) 1898 →

All 54 seats in the Minnesota Senate
28 seats needed for a majority
  Majority party Minority party Third party
 
GOP
PEO
DEM
Party Republican Populist Democratic
Seats won 46 5 3
Seat change Increase20 New Decrease12
Popular vote 148,421 46,912 77,418
Percentage 52.0% 16.4% 27.1%

The 1894 Minnesota Senate election was held in the U.S. state of Minnesota on November 6, 1894, to elect members to the Senate of the 29th and 30th Minnesota Legislatures.

The Minnesota Republican Party won a large majority of seats, followed by the new People's Party and the Minnesota Democratic Party. The new Legislature convened on January 8, 1895.

Numerous Democratic candidates were also endorsed by the People's Party, and one was also endorsed by the Prohibition Party. However, all planned to caucus with the Democrats in the Senate, and are thus listed as part of their total.[1]

Results

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Summary of the November 6, 1894 Minnesota Senate election results
Party Candidates Votes Seats
No. %
Republican Party 53 148,421 46 52.02
People's Party 36 46,912 5 16.44
Democratic Party 44 77,418 3 27.13
Prohibition Party 11 4036 0 1.41
Independent 12 8,523 0 2.99
Total 285,310 54 100.00
Source: Minnesota Secretary of State[2]

*These totals count candidates endorsed by the Democratic and People's Parties in the totals for the Democratic Party.

See also

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References

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  1. ^ 1895 Minnesota Legislative Manual. Minnesota Secretary of State. 1895. pp. 471–479.
  2. ^ "Election Results - Minnesota Legislative Reference Library". www.leg.state.mn.us. Retrieved January 7, 2020.