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1844 United States presidential election in New Jersey

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1844 United States presidential election in New Jersey

← 1840 November 1 - December 4, 1844 1848 →
 
Nominee Henry Clay James K. Polk
Party Whig Democratic
Home state Kentucky Tennessee
Running mate Theodore Frelinghuysen George M. Dallas
Electoral vote 7 0
Popular vote 38,318 37,495
Percentage 50.46% 49.37%

County Results

President before election

John Tyler
Independent

Elected President

James K. Polk
Democratic

The 1844 United States presidential election in New Jersey took place between November 1 and December 4, 1844, as part of the 1844 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.

New Jersey voted for the Whig candidate, Henry Clay, over Democratic candidate James K. Polk. Clay won New Jersey by a margin of 1.09 percent; however, Polk would be the last Democrat to carry Cape May County until Woodrow Wilson in 1912.[1] This is the last time a Democrat won without carrying Hudson County.

Results

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1844 United States presidential election in New Jersey[2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Whig Henry Clay of Kentucky Theodore Frelinghuysen of New York 38,318 50.46% 7 100.00%
Democratic James K. Polk of Tennessee George M. Dallas of Pennsylvania 37,495 49.37% 0 0.00%
Liberty James G. Birney of Michigan Thomas Morris of Ohio 131 0.17% 0 0.00%
Total 75,944 100.00% 7 100.00%

See also

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References

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  1. ^ Menendez, Albert J.; The Geography of Presidential Elections in the United States, 1868-2004, pp. 258-259 ISBN 0786422173
  2. ^ "1844 Presidential General Election Results – New Jersey". U.S. Election Atlas. Retrieved December 23, 2013.